• question_answer In the statement "an eccentric mass rotating a 3000 rpm will create X times more unbalanced force than 50% of the same mass rotating at 300 rpm", 'X' stands for: A) 10                                B) 50C) 100                              D) 200

Solution :

Unbalanced force, $F=me{{\omega }^{2}}$ $\omega =\frac{2\pi N}{60}$             $\therefore \,\,\,\,\,\,\,F\propto m{{N}^{2}}$ $\frac{{{F}_{1}}}{{{F}_{2}}}=\frac{{{m}_{1}}N_{1}^{2}}{{{m}_{1}}N_{2}^{2}}=\frac{m}{\left( \frac{m}{2} \right)}\times \left( \frac{3000}{300} \right)=2\times 100=200$

You need to login to perform this action.
You will be redirected in 3 sec