question_answer

A shaft, supported on two bearings at its ends, carries two flywheels 'L' apart. Mass moment of inertia of the two flywheels are \[{{l}_{a}}\] and \[{{l}_{b}}\] I being the polar moment of inertia of cross-sectional area of inertia of shaft. Distance \[{{l}_{a}}\] of the node of torsional vibration of the shaft from the flywheel la is \[{{l}_{a}}\] given by: 

A) \[{{l}_{a}}=\frac{L{{l}_{b}}}{{{I}_{a}}+{{I}_{b}}}\]                       

B) \[{{l}_{a}}=\frac{L{{l}_{a}}}{{{I}_{a}}+{{I}_{b}}}\]

C) \[{{l}_{a}}=\frac{L{{l}_{b}}}{{{I}_{a}}+{{I}_{b}}-1}\]        

D) \[{{l}_{a}}=\frac{L{{l}_{a}}}{{{I}_{a}}+{{I}_{b}}-1}\]