A) \[{{l}_{a}}=\frac{L{{l}_{b}}}{{{I}_{a}}+{{I}_{b}}}\]
B) \[{{l}_{a}}=\frac{L{{l}_{a}}}{{{I}_{a}}+{{I}_{b}}}\]
C) \[{{l}_{a}}=\frac{L{{l}_{b}}}{{{I}_{a}}+{{I}_{b}}-1}\]
D) \[{{l}_{a}}=\frac{L{{l}_{a}}}{{{I}_{a}}+{{I}_{b}}-1}\]
Correct Answer: A
Solution :
\[{{I}_{a}}=\left( \frac{{{I}_{b}}}{{{I}_{a}}+{{I}_{b}}} \right)\,L\]You need to login to perform this action.
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