A) \[0.146\,\,\text{N/}{{\text{m}}^{\text{2}}}\]
B) \[0.73\,\,\text{N/}{{\text{m}}^{\text{2}}}\]
C) \[146\,\,\text{N/}{{\text{m}}^{\text{2}}}\]
D) \[292\,\,\text{N/}{{\text{m}}^{\text{2}}}\]
Correct Answer: D
Solution :
\[p\,\,=\,\,\frac{4\sigma }{d}\,\,=\,\,\frac{4\,\,\times \,\,0.073}{1\,\,\times \,\,{{10}^{-\,3}}}\] \[=\,\,292\,\,\text{N/}{{\text{m}}^{\text{2}}}\]
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