A) 0.2
B) 0.4
C) 0.8
D) 1.0
Correct Answer: C
Solution :
Radiosity, \[J=\varepsilon {{E}_{b}}+(1-\varepsilon )G\] Where G = Irradiation \[=20\,\,\text{W/}{{\text{m}}^{\text{2}}}\] \[{{E}_{b}}=\] emissive power \[=10\,\,\text{W/}{{\text{m}}^{\text{2}}}\] \[I=12\,\,\text{W/}{{\text{m}}^{\text{2}}}\] \[12=\varepsilon \times 10+(1-\varepsilon )\times 20\] \[\varepsilon =0.8\]
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