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JEE Main & Advanced Physics Wave Mechanics Question Bank Vibration of String

  • question_answer
    The tension of a stretched string is increased by 69%. In order to keep its frequency of vibration constant, its length must be increased by                                                    [KCET 2002]

    A)            20%                                          

    B)            30%

    C)            \[\sqrt{69}%\]                     

    D)            69%

    Correct Answer: B

    Solution :

                         \[n\propto \frac{\sqrt{T}}{l}\]\[\Rightarrow l\propto \sqrt{T}\]                                               (As \[n\]= constant)                    Þ\[\frac{{{l}_{2}}}{{{l}_{1}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}={{l}_{1}}\sqrt{\frac{169}{100}}\Rightarrow {{l}_{2}}=1.3{{l}_{1}}={{l}_{1}}+30%\] of \[{{l}_{1}}\]


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