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JEE Main & Advanced Physics Wave Mechanics Question Bank Vibration of String

  • question_answer
    A stretched string of 1m length and mass \[5\times {{10}^{-4}}kg\] is having tension of 20N. If it is plucked at 25cm from one end then it will vibrate with frequency [RPET 1999; RPMT 2002]

    A)            100 Hz                                     

    B)            200 Hz

    C)            256 Hz                                     

    D)            400 Hz

    Correct Answer: B

    Solution :

                         As we know plucking distance from one end \[=\frac{l}{2p}\]                    Þ \[25=\frac{100}{2p}\] Þ \[p=2\]. Hence frequency of vibration \[n=\frac{p}{2l}\sqrt{\frac{T}{m}}=\frac{2}{2\times 1}\sqrt{\frac{20}{5\times {{10}^{-4}}}}\] = \[200Hz.\]


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