A) 30 ml
B) 15 ml
C) 40 ml
D) 60 ml
Correct Answer: A
Solution :
\[0.1M\ \text{of}\ {{H}_{2}}S{{O}_{4}}\ \Rightarrow \ 0.2\,N\ \text{of}\ {{H}_{2}}S{{O}_{4}}\] \ N1V1 = N2V2 [\[N=2m\] for \[{{H}_{2}}S{{O}_{4}}\]] 0.2 × V1=30 × 0.2 \ V1 = 30 ml
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