A) 45
B) 53
C) 40
D) 63
Correct Answer: D
Solution :
20 ml of 0.1N \[NaOH\]neutralize 20 ml of 0.1N acid \[\text{Weight}\,\,\text{of}\,\,\text{acid}=0.126\,\,g\] Volume = 20 ml=\[\frac{20}{1000}litre\] Normality = 0.1 N Equivalent weight = ? \[\text{Equivalent}\,\,\text{weight}=\frac{\text{weight}\,\,\text{of}\,\,\text{acid}}{N\times V}\] \[=\frac{0.126\times 1000}{0.1\times 20}=63\]
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