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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    15 ml of \[{N}/{10}\;\]  \[NaOH\] solution completely neutralises 12 ml of \[{{H}_{2}}S{{O}_{4}}\] solution. The normality of \[{{H}_{2}}S{{O}_{4}}\] solution will be [MP PET 1995]

    A) \[{N}/{5}\;\]

    B) \[{N}/{10}\;\]

    C) \[{N}/{{}}\;8\]

    D) \[N\]

    Correct Answer: C

    Solution :

    \[{{N}_{1}}{{V}_{1}}\ =\ {{N}_{2}}{{V}_{2}}\],     \[\frac{1}{10}\ \times \ 15\ =\ {{N}_{2}}\ \times \ 12\ \Rightarrow \ {{N}_{2}}\ =\ \frac{1}{8}\ N\]


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