A) 1.12 litre
B) 0.84 litre
C) 2.24 litre
D) 4.06 litre
Correct Answer: A
Solution :
\[BaC{{O}_{3}}\to BaO+C{{O}_{2}}\uparrow \] \[\therefore 197\,g\,\,BaC{{O}_{3}}\]on decompose gives = 22.4 litre \[C{{O}_{2}}\] \[\therefore 1\,g\,\,BaC{{O}_{3}}\]will give =\[\frac{22.4}{197}=litre\,\,C{{O}_{2}}\] \[=\frac{22.4\times 9.85}{197}=1.12\,\,litre\,\,C{{O}_{2}}\]
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