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JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    In the reaction \[{{I}_{2}}+2{{S}_{2}}O_{3}^{-}\to 2{{l}^{-}}+{{S}_{4}}O_{6}^{2-};\] the equivalent weight of iodine will be equal to [MNR 1985; UPSEAT 2000]

    A) Molecular weight

    B) 1/2 the molecular weight

    C) 1/4 the molecular weight

    D) Twice the molecular weight

    Correct Answer: B

    Solution :

    \[\underset{(O)}{\mathop{{{I}_{2}}}}\,+2{{S}_{2}}O_{3}^{-}\to \underset{(-2)}{\mathop{2{{I}^{-}}}}\,+{{S}_{4}}O_{6}^{2-}\] \[\therefore \] Eq. wt. = \[\frac{1}{2}\ \times \ \text{molecular wt}\text{.}\]


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