JEE Main & Advanced Chemistry Analytical Chemistry Question Bank Volumetric Analysis

  • question_answer
    To neutralise 10 ml of \[{M}/{5}\;\]\[NaOH\] the volume of \[{M}/{20}\;\] \[HCl\] required is [EAMCET 1980]

    A) 10 ml

    B) 15 ml

    C) 40 ml

    D) 25 ml

    Correct Answer: C

    Solution :

    \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] Þ  \[\frac{1}{5}\ \times 10\ =\ \frac{1}{20}\ \times \ {{V}_{2}}\ \Rightarrow \ {{V}_{2}}\ =\ 40\ ml\]


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