A) 0.925 g
B) 0.0125 g
C) 0.25 g
D) 1 g
Correct Answer: A
Solution :
We know, \[[{{H}^{+}}]\ ={{10}^{-pH}}={{10}^{-13}};\] \[\therefore \ [O{{H}^{-}}]=\frac{{{10}^{-14}}}{{{10}^{-13}}}={{10}^{-1}}\] Hence, normality of solution = 0.1 We know, w = \[\frac{NEV}{1000}=\frac{0.1\times 74\times 250}{2\times 1000}=0.925\ gm\]
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