A) 40 \[c{{m}^{3}}\]
B) 30 \[c{{m}^{3}}\]
C) 20 \[c{{m}^{3}}\]
D) 10 \[c{{m}^{3}}\]
Correct Answer: C
Solution :
Normality = molarity × basicity or acidity (for HCl) \[{{N}_{2}}=0.4\times 1=0.4N\]Basicity =1 (for NaOH acidity =1) \[{{N}_{1}}=0.6\times 1=0.6N\] \[{{V}_{1}}=?\ {{V}_{2}}=30\ c{{m}^{3}}\] From the equation, \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[0.6\times {{V}_{1}}=0.4\times 30\] \[{{V}_{1}}=\frac{0.4\times 30}{0.6}=20\ c{{m}^{3}}\]
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