A) \[{{S}_{4}}O_{6}^{2-}+{{I}^{-}}\]
B) \[SO_{4}^{2-}+{{I}^{-}}\]
C) \[S{{O}_{3}}+{{I}^{-}}\]
D) \[{{S}_{4}}O_{6}^{2-}+I_{3}^{-}\]
Correct Answer: A
Solution :
\[{{I}_{2}}+N{{a}_{2}}{{S}_{2}}{{O}_{3}}\to 2NaI+N{{a}_{2}}{{S}_{4}}{{O}_{6}}\] \[{{I}_{2}}+{{S}_{2}}O_{3}^{2-}\to 2{{I}^{-}}+{{S}_{4}}O_{6}^{2-}\]
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