A) 9 : 1
B) 3 : 1
C) 25 : 9
D) 16 : 25
Correct Answer: A
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}+1}{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}-1} \right)}^{2}}={{\left( \frac{\sqrt{\frac{4}{1}}+1}{\sqrt{\frac{4}{1}}-1} \right)}^{2}}=\frac{9}{1}\]
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