A) 5 : 2
B) 7 : 3
C) 49 : 9
D) 9 : 49
Correct Answer: C
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}+1}{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}-1} \right)}^{2}}={{\left( \frac{\sqrt{\frac{25}{4}}+1}{\sqrt{\frac{25}{4}}-1} \right)}^{2}}=\frac{49}{9}\]
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