A) 25 : 1
B) 5 : 1
C) 9 : 4
D) 25 : 16
Correct Answer: C
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}+1}{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}-1} \right)}^{2}}\Rightarrow \frac{{{I}_{1}}}{{{I}_{2}}}=\frac{9}{4}\]You need to login to perform this action.
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