A) 100 J
B) 200 J
C) 300 J
D) 400 J
Correct Answer: C
Solution :
\[100=\frac{1}{2}k{{x}^{2}}\] (given) \[W=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})=\frac{1}{2}k[{{(2x)}^{2}}-{{x}^{2}}]\] \[=3\times \left( \frac{1}{2}k{{x}^{2}} \right)=3\times 100=300\,J\]
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