JEE Main & Advanced Physics Work, Energy, Power & Collision / कार्य, ऊर्जा और शक्ति Question Bank Work Done by Variable Force

  • question_answer
    A spring when stretched by 2 mm its potential energy becomes 4 J. If it is stretched by 10 mm, its potential energy is equal to                          [BCECE 2003]

    A)             4 J      

    B)             54 J

    C)             415 J  

    D)             None

    Correct Answer: D

    Solution :

                    \[U=\frac{1}{2}k{{x}^{2}}\] if x becomes 5 times then energy will become 25 times i.e. \[4\times 25=100\,J\]

You need to login to perform this action.
You will be redirected in 3 sec spinner