JEE Main & Advanced Physics Work, Energy, Power & Collision Question Bank Work Done by Variable Force

  • question_answer
    A spring of spring constant 5 ´ 103 N/m is stretched initially by 5cm from the unstretched position. Then the work required to stretch it further by another  \[5cm\] is                       [AIEEE 2003]

    A)             6.25 N-m        

    B)             12.50 N-m

    C)             18.75 N-m

    D)               25.00 N-m

    Correct Answer: C

    Solution :

                    \[W=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})=\frac{1}{2}\times 5\times {{10}^{3}}({{10}^{2}}-{{5}^{2}})\times {{10}^{-4}}\]             \[=18.75\,J\]

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