JEE Main & Advanced Physics Work, Energy, Power & Collision Question Bank Work Done by Variable Force

  • question_answer
    The spring extends by x on loading, then energy stored by the spring is : (if T is the tension in spring and k is spring constant)                                                             [Pb. PMT 2003]

    A)             \[\frac{{{T}^{2}}}{2k}\]    

    B)             \[\frac{{{T}^{2}}}{2{{k}^{2}}}\]

    C)             \[\frac{2k}{{{T}^{2}}}\]    

    D)             \[\frac{2{{T}^{2}}}{k}\]

    Correct Answer: A

    Solution :

                    \[U=\frac{{{F}^{2}}}{2k}=\frac{{{T}^{2}}}{2k}\]


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