A) 0.1 joule
B) 0.2 joule
C) 0.3 joule
D) 0.5 joule
Correct Answer: A
Solution :
DP.E.\[=\frac{1}{2}k(x_{2}^{2}-x_{1}^{2})=\frac{1}{2}\times 10[{{(0.25)}^{2}}-{{(0.20)}^{2}}]\] \[=5\times 0.45\times 0.05=0.1\,J\]
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