JEE Main & Advanced Physics Work, Energy, Power & Collision Question Bank Work Done by Variable Force

  • question_answer Two springs of spring constants 1500 N/m and 3000 N/m respectively are stretched with the same force. They will have potential energy in the ratio [MP PMT/PET 1998; Pb. PMT 2002]

    A)             4 : 1    

    B)             1 : 4

    C)             2 : 1    

    D)             1 : 2

    Correct Answer: C

    Solution :

                    \[U=\frac{{{F}^{2}}}{2k}\]Þ \[\frac{{{U}_{1}}}{{{U}_{2}}}=\frac{{{k}_{2}}}{{{k}_{1}}}\]            (if force are same)             \ \[\frac{{{U}_{1}}}{{{U}_{2}}}=\frac{3000}{1500}=\frac{2}{1}\]

adversite


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