• # question_answer The force constant of a wire is k and that of another wire is $2k.$ When both the wires are stretched through same distance, then the work done                           [MH CET 2000] A)             ${{W}_{2}}=2W_{1}^{2}$ B)               ${{W}_{2}}=2{{W}_{1}}$ C)             ${{W}_{2}}={{W}_{1}}$ D)               ${{W}_{2}}=0.5{{W}_{1}}$

$W=\frac{1}{2}k{{x}^{2}}$             If both wires are stretched through same distance then $W\propto k$. As ${{k}_{2}}=2{{k}_{1}}$ so ${{W}_{2}}=2{{W}_{1}}$