JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    The Young's modulus of a wire is Y.  If the energy per unit volume is E, then the strain will be

    A)                 \[\sqrt{\frac{2E}{Y}}\]

    B)                 \[\sqrt{2EY}\]

    C)                 EY          

    D)                 \[\frac{E}{Y}\]

    Correct Answer: A

    Solution :

    Energy per unit volume \[=\frac{1}{2}\times \text{Y}\times {{(\text{strain)}}^{\text{2}}}\]             \[\therefore \text{strain}=\sqrt{\frac{\text{2}E}{Y}}\]         


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