2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Elasticity

JEE Main & Advanced Physics Elasticity Question Bank Work Done in Stretching a Wire

  • question_answer
    The ratio of Young's modulus of the material of two wires is 2 : 3. If the same stress is applied on both, then the ratio of elastic energy per unit volume will be

    A) 3 : 2       

    B)                 2 : 3

    C)                 3 : 4       

    D)                 4 : 3

    Correct Answer: A

    Solution :

    Energy per unit volume = \[\frac{{{(\text{stress)}}^{\text{2}}}}{2Y}\]             \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{Y}_{2}}}{{{Y}_{1}}}\] (Stress is constant)\ \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{3}{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner