Answer:
Kinetic energy, \[K=\frac{1}{2}m{{\upsilon }^{2}}=\frac{{{(m\upsilon )}^{2}}}{2m}=\frac{{{p}^{2}}}{2m}\] or \[p=\sqrt{2mK}\] i.e., \[p\propto \sqrt{m}\] Thus the heavier body has a greater momentum than the lighter one.
You need to login to perform this action.
You will be redirected in
3 sec