A) 0
B) 6 m
C) 12m
D) 18m
Correct Answer: A
Solution :
Given, \[t=\sqrt{x}+3\] \[\Rightarrow \] \[x={{(t-3)}^{2}}\] ? (i) \[\therefore \] \[v=\frac{dx}{dt}=2(t-3)=0\] \[\Rightarrow \] \[t=\sec \] Putting it in equation (i), we get \[x={{(3-3)}^{2}}=\mathbf{0}\]You need to login to perform this action.
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