A) 0.30 mm
B) 0.40 mm
C) 0.53 mm
D) 450 micron
Correct Answer: A
Solution :
\[\beta =\frac{\lambda D}{d};\ \ \therefore B\propto \lambda \] \[\frac{\lambda '}{\lambda }=\frac{0.4}{4/3}\Rightarrow \lambda '=0.3\ mm\].
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