JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In Young's double slit experiment, if the widths of the slits are in the ratio 4 : 9, the ratio of the intensity at maxima to the intensity at minima will be                             [Manipal MEE 1995]

    A)            169 : 25                                   

    B)            81 : 16

    C)            25 : 1                                        

    D)            9 : 4

    Correct Answer: C

    Solution :

                       Slit width ratio \[=4:9;\]hence \[{{I}_{1}}:{{I}_{2}}=4:9\]                    \[\therefore \frac{a_{1}^{2}}{a_{2}^{2}}=\frac{4}{9}\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{2}{3}\]            \[\therefore \frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{({{a}_{1}}+{{a}_{2}})}^{2}}}{{{({{a}_{1}}-{{a}_{2}})}^{2}}}=\frac{25}{1}\]


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