A) Increase of\[589\,\,{AA}\]
B) Decrease of\[589\,\,{AA}\]
C) Increase of\[6479\,\,{AA}\]
D) Zero
Correct Answer: A
Solution :
\[\theta =\frac{\lambda }{d};\theta \]can be increased by increasing l, so here l has to be increased by 10% i.e., % Increase \[=\frac{10}{100}\times 5890=589{AA}\]
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