JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In Young's experiment, the distance between slits is 0.28 mm and distance between slits and screen is 1.4 m. Distance between central bright fringe and third bright fringe is 0.9 cm. What is the wavelength of used light            [KCET 1999]

    A) \[5000\,\,{AA}\]

    B) \[6000\,\,{AA}\]

    C) \[7000\,\,{AA}\]

    D) \[9000\,\,{AA}\]

    Correct Answer: B

    Solution :

    Position of 3rd bright fringe \[{{x}_{3}}=\frac{3D\lambda }{d}\]  \[\Rightarrow \lambda =\frac{{{x}_{3}}d}{3D}=\frac{(0.9\times {{10}^{-2}})\times (0.28\times {{10}^{-3}})}{3\times 1.4}=6000{AA}\]


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