JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    Young?s double slit experiment is performed with light of wavelength 550 nm. The separation between the slits is 1.10 mm and screen is placed at distance of 1 m. What is the distance between the consecutive bright or dark fringes [Pb. PMT 2000]

    A)            1.5 mm                                   

    B)            1.0 mm

    C)            0.5 mm                                   

    D)            None of these

    Correct Answer: C

    Solution :

                       Distance between consecutive bright fringes or dark fringes\[=\beta \] \[\beta =\frac{\lambda D}{d}=\frac{550\times {{10}^{-9}}\times 1}{1.1\times {{10}^{-3}}}=500\times {{60}^{-6}}=0.5\ mm\]


You need to login to perform this action.
You will be redirected in 3 sec spinner