JEE Main & Advanced Physics Wave Optics Question Bank Young's Double Slit Experiment and Biprism

  • question_answer In Young?s experiment, the ratio of maximum to minimum intensities of the fringe system is 4 : 1. The amplitudes of the coherent sources are in the ratio   [RPMT 1996; MP PET 2000; RPET 2001; MP PMT 2001]

    A)            4 : 1                                          

    B)            3 : 1

    C)            2 : 1                                          

    D)            1 : 1

    Correct Answer: B

    Solution :

               \[\frac{{{I}_{\max }}}{{{I}_{\min }}}=\frac{{{\left( \frac{{{a}_{1}}}{{{a}_{2}}}+1 \right)}^{2}}}{{{\left( \frac{{{a}_{1}}}{{{a}_{2}}}-1 \right)}^{2}}}=\frac{4}{1}\Rightarrow \frac{{{a}_{1}}}{{{a}_{2}}}=\frac{3}{1}\]

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