A) 34
B) 40
C) 25
D) 38
Correct Answer: A
Solution :
\[\frac{{{I}_{\max }}}{{{I}_{\min }}}={{\left( \frac{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}+1}{\sqrt{\frac{{{I}_{1}}}{{{I}_{2}}}}-1} \right)}^{2}}={{\left( \frac{\sqrt{2}+1}{\sqrt{2}-1} \right)}^{2}}\approx 34;\] (given I1 = 2I2)
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