A) 3
B) \[\frac{1}{3}\]
C) 9
D) \[\frac{1}{9}\]
Correct Answer: A
Solution :
\[\beta \propto \frac{\lambda }{d}\] as \[d\to \frac{d}{3}\] so \[\beta \to 3\beta \] \[\therefore \,\,\,n=3\]
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