JEE Main & Advanced Physics Wave Optics / तरंग प्रकाशिकी Question Bank Young's Double Slit Experiment and Biprism

  • question_answer
    In a Young?s double slit experiment, the slit separation is 0.2 cm, the distance between the screen and slit is 1m. Wavelength of the light used is 5000 Å. The distance between two consecutive dark fringes (in mm) is [DCE 2004]

    A)            0.25                                          

    B)            0.26

    C)            0.27                                          

    D)             0.28

    Correct Answer: A

    Solution :

               Distance between two consecutive dark fringes  \[\beta =\frac{\lambda D}{d}\] \[=\frac{5000\times {{10}^{-10}}\times 1}{0.2\times {{10}^{-2}}}=0.25\]mm.


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