A) Phase difference of \[3\pi \]
B) Phase difference of \[\frac{5\pi }{2}\]
C) Path difference of \[3\lambda \]
D) Path difference of \[\frac{5\lambda }{2}\]
Correct Answer: D
Solution :
For minima, path difference \[\Delta =(2n-1)\frac{\lambda }{2}\] For third minima \[n=3\Rightarrow \Delta =(2\times 3-1)\frac{\lambda }{2}=\frac{5\lambda }{2}\]
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