A) 9.6 m
B) \[9.6\times {{10}^{3}}\,m\]
C) \[19.2\times {{10}^{-2}}\,m\]
D) \[9.6\times {{10}^{-2}}\,m\]
Correct Answer: D
Solution :
\[l=\frac{{{L}^{2}}dg}{2Y}\]\[=\frac{{{(8)}^{2}}\times 1.5\times {{10}^{3}}\times 10}{2\times 5\times {{10}^{6}}}=9.6\times {{10}^{-2}}m\]You need to login to perform this action.
You will be redirected in
3 sec