(i) Give all the possible genotypes of the members 4, 5 and 6 in the pedigree chart. |
(ii) A blood test shows that the individual 14 is a carrier of haemophilia. The member numbered as 15 got recently married to number 14. What is the probability that their first child will be a haemophilic male? |
Answer:
(i) Possible genotype of member 4 is XX or \[X{{X}^{h}}\] Possible genotype of member 5 is \[{{X}^{h}}Y\] Possible genotype of member 6 is XY. (ii) According to the given pedigree, if the member 15 gets married to the member 14 of this family then the probability of first child to be a haemophilia male will be 25%. Thus, heterozygous female (carrier) for haemophilia may transmit the disease to her sons.
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