Answer:
Reaction with benzene sulphonyl chloride
(Hinsberg's reagent)
(i) Secondary amine (
) N.N-di alkyI
benzene sulphonamide is formed. It is insoluble in alkali due to lack of acidic
hydrogen.
Tertiary amine (
) It does
not react with
Hinsberg's reagent.
(ii) Aniline
[1]
It gives dye test. Add 
dilute to
aniline in HCl and cool at 273K. Add ice-cold alkaline solution of phenol.
Bright orange dye is formed.
It does not give dye test but with 
it forms
benzyl alcohol with liberation of 
.
[1]
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