A) 2.4 cm
B) 2.6 cm
C) 3.4 cm
D) 4.8 cm
Correct Answer: A
Solution :
\[V\propto {{r}^{2}}\] \[\Rightarrow \] \[V=K{{r}^{2}}\] \[2=K\times {{(1.5)}^{2}}\Rightarrow \,K=\frac{2}{2.25}\] \[K=\frac{8}{9}\] Again, \[5=\frac{8}{9}\times {{r}^{2}}\] \[\Rightarrow \] \[{{r}^{2}}=\frac{5\times 9}{8}\] \[\therefore \] \[r=\frac{3}{2}\times \sqrt{\frac{5}{2}}\] \[=1.5\times \sqrt{2.5}=1.5\times 1.6=2.4\,cm\] Hence, required radius = 2.4 cm
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