A) Rs 12000, 5%
B) Rs 6000, 8%
C) Rs 8000, 6%
D) Rs 10000, 8.5%
Correct Answer: C
Solution :
\[\frac{P{{\left( 1+\frac{r}{100} \right)}^{3}}}{P{{\left( 1+\frac{r}{100} \right)}^{2}}}=\left( 1+\frac{r}{100} \right)\] \[\therefore \] \[\frac{9528.128}{8988.8}=\left( 1+\frac{r}{100} \right)\] \[\Rightarrow \] \[\left( 1+\frac{84270}{1404500} \right)=\,\left( 1+\frac{r}{100} \right)\] \[\Rightarrow \] \[\left( 1+\frac{6}{100} \right)=\left( 1+\frac{r}{100} \right)\] \[\Rightarrow \] \[r=6%\] So, \[8988.8=P{{\left( 1+\frac{6}{100} \right)}^{3}}\] \[\therefore \] \[P=8000\]
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