A) 1
B) 2
C) 3
D) None of these
Correct Answer: C
Solution :
Given, \[\frac{3-4\,{{\sin }^{2}}\theta }{{{\cos }^{2}}\theta }+{{\tan }^{2}}\theta \] \[=\frac{3}{{{\cos }^{2}}\theta }4\,{{\tan }^{2}}\theta +{{\tan }^{2}}\theta \] \[=3{{\sec }^{2}}\theta -3{{\tan }^{2}}\theta \] \[=3({{\sec }^{2}}\theta -{{\tan }^{2}}\theta )\] \[({{\sec }^{2}}\theta -{{\tan }^{2}}\theta =1)\] \[=3\times 1=3\]
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