A) Rs.1500
B) Rs.1600
C) Rs.1700
D) Rs.1800
Correct Answer: A
Solution :
Let \[x\] be the sum of amount. \[\therefore \] \[SI=\frac{x\times 3\times 10}{100}=\frac{3x}{10}\] and \[CI=x{{\left( 1+\frac{10}{100} \right)}^{3}}-x\] \[=x\times {{\left( \frac{11}{10} \right)}^{3}}-x\] \[\Rightarrow \] \[x\left[ {{\left( \frac{11}{10} \right)}^{3}}-1 \right]-\left( \frac{3x}{10} \right)=46.5\] \[\Rightarrow \] \[x(1.331-1)-\frac{3x}{10}=46.5\] \[\Rightarrow \] \[x(0.331-0.3)=46.5\] \[\Rightarrow \] \[x=\frac{46.5}{0.031}=\frac{46500}{31}=\text{Rs}\,1500\]
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