A) \[{{n}^{2}}\,yr\]
B) \[2{{n}^{2}}\,yr\]
C) 2n yr
D) 4 n yr
Correct Answer: C
Solution :
Since, \[A=2P,\] then \[2P=P\,{{\left( 1+\frac{r}{100} \right)}^{n}}\] \[\Rightarrow \] \[2=\,{{\left( 1+\frac{r}{100} \right)}^{n}}\] \[\Rightarrow \] \[4={{(2)}^{2}}={{\left[ {{\left( 1+\frac{r}{100} \right)}^{n}} \right]}^{2}}={{\left( 1+\frac{r}{100} \right)}^{2n}}\] \[\Rightarrow \] Time period = 2n yr \[[{{({{a}^{m}})}^{n}}={{a}^{mn}}]\]
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