A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) \[\frac{3}{4}\]
D) \[\frac{1}{3}\]
Correct Answer: B
Solution :
Sample space, \[S=\{HH,\,HT,\,TH,\,TT\}\] Number of exhaustive cases = 4 There is only one favorable case \[\{TT\}\] \[\therefore \] \[P(2\,tails)=\frac{1}{h}\]
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