• question_answer In an alloy, the ratio of copper and zinc is 5:2. If 1.250 kg of zinc is mixed in 17 kg 500 g of alloy, then the ratio of copper and zinc will be A)  2 : 1            B)  2 : 3 C)  3:2            D)  1 : 2

Weight of copper in 17 kg 500 g i.e., 17500 g of alloy $=\frac{5}{7}\times 17500=12500\,g$ and weight of zinc = (17500 -12500) = 5000 g Since, 1250 g of zinc is mixed in alloy. $\therefore$ Total weight of zinc = 1250 + 5000 = 6250 g $\therefore$ Required ratio = 12500: 6250 = 2 : 1